Question

+---------+-------------------+------+------+
| NAME    | TITLE             | SIZE | RANK |
+---------+-------------------+------+------+
| A       | Hippo             | H    |  1   |
| A       | Hippo             | M    |  1   |
| A       | Hippo             | H    | N/A  |
| A       | Hippo             | H    |  1   |
| A       | Hippo             | H    | N/A  |
| B       | Snail             | H    |  1   |
| B       | Snail             | M    |  1   |
| B       | Snail             | L    |  1   |
| C       | Dog               | H    |  1   |
| C       | Dog               | M    |  1   |
+---------+-------------------+------+------+

Example of exact data pulled from above

+---------+-------------------+------+------+
| A       | Hippo             | H    |  1   |
| A       | Hippo             | M    |  1   |
| A       | Hippo             | H    | N/A  |
| A       | Hippo             | H    |  1   |
| A       | Hippo             | H    | N/A  |
+---------+-------------------+------+------+

Points are as follows:

H = 70 points
M = 20 points
L = 10 points

• Hippo has 4 H in size column.
• H in total can equal 70.
• Therefore 70/4 = 17.5
• This means each single H can only have 17.5 points.
• Points are aquired if ‘Rank’ is present.
• Hippo has only two ‘Rank’ present.
• Therefore Hippo gains (17.5)x(2)=35 points.
• Hippo also has an M present in ‘size’ column.
• Therefore M = 20/1 =20.
• Therefore hippo gains 20 points.
• Hippo has no L in size column.
• Therefore no points gained.
• Which totals 35 (from H) + 20 (from M) + 0 (from L) = 55.

Desired output

+---------+----------+-------+
| NAME    | TITLE    | SCORE |
+---------+----------+-------+
| A       | Hippo    |   55  |
| B       | Snail    |  100  |
| C       | Dog      |   90  |
+---------+----------+-------+

How do you do this type of complex scoring/variable handling in MySQl

Answer 1

after a complex sub select and joins, here is the result you are expecting:

select c.name,c.title,sum(score) from (
select b.name, b.title, avg_point*needcount as score from (select name, title, size,    count(size),  (case when size='H' then 70 when size='M' then 20 when size='L' then 10 end )/ count(size)  as avg_point from points group by name,title,size ) a
join 
(select name, title, size, count(size) as needcount from points where rank group by name, title, size) b
on a.name = b.name
and a.title = b.title
and a.size = b.size) c group by c.name,c.title;