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Home/ Questions/Q 9077381
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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T19:19:40+00:00 2026-06-16T19:19:40+00:00

Need some help with Python syntax Pesudo code if param is not None in

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Need some help with Python syntax

Pesudo code

if param is not None in params, param replace(‘xx’, ‘x’)

I get this far:

param.replace('|', '/') for param in ("bar|one","bar|two")

My question is how to add a None check in this line of code?

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  1. Editorial Team
    Editorial Team
    2026-06-16T19:19:41+00:00Added an answer on June 16, 2026 at 7:19 pm

    Perhaps:

    [ param.replace("|", "/") if param is not None else None for param in iterable ]
    

    Or maybe a tiny bit more legible if we switch the logic around just a bit:

    [ None if param is None else param.replace("|", "/") for param in iterable ]
    

    I like the second version a little better because if breaks up the None else None nonsense that was present in the first one…

    This differs slightly from the (initial) answer by @Tim Pietzcker. His (initial) answer will filter None values out of the input iterable whereas this answer will pass them through.


    Here we use the python conditional expression (which is sometimes known as the “ternary operator” in other languages). The syntax is:

    value_if_true if conditional_expression else value_if_false
    
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