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Home/ Questions/Q 6798571
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T18:44:47+00:00 2026-05-26T18:44:47+00:00

Need to pass get parameter without value and without = symbol to utilize external

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Need to pass get parameter without value and without “=” symbol to utilize external API. The URL is

http://example.com/Service/v1/service.ashx?methodName&name=val&blablabla

As you could see first parameter is the name of the method (methodName) to be called on the server and it does not have any value nor “=”.
I want to form parameters in “right” way but at the moment forming them like below:

    List<NameValuePair> params = new LinkedList<NameValuePair>();
    params.add(new BasicNameValuePair("name", "val"));
    params.add(new BasicNameValuePair("name1", "val1"));

    String paramString = URLEncodedUtils.format(params, "utf-8");

    HttpClient client = new DefaultHttpClient();
    HttpGet httpGet = new HttpGet(getEndpointUrl() + "?methodName&" + paramString);

The problem is in last line where concatenation is used (instead of regular conversion of params). Adding “methodName” as name to params and null as value gives “methodName=” in resulting URL. Server does not understand such notation.

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  1. Editorial Team
    Editorial Team
    2026-05-26T18:44:47+00:00Added an answer on May 26, 2026 at 6:44 pm

    I think you’d be better off forming the URL manually. We use HttpGet methods extensively, and when we construct URL strings, we do so manually to ensure parameter ‘correctness’. We then use URIUtil from the HttpClient project to encode the query string:

    // Start with your base method name, if necessary/known
    String paramString = "methodName";
    for (NameValuePair p : params ) {
        String n = p.getName();
        String v = p.getValue();
        if ( v == null ) {
            paramString += "&" + n;
        } else {
            paramString += "&" + n + "=" + v;
        }
    }
    
    String url = "http://example.com/Service/v1/service.ashx?" + URIUtil.encodeQuery(paramString);
    HttpGet get = new HttpGet(url);
    
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