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Home/ Questions/Q 7808293
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T03:05:50+00:00 2026-06-02T03:05:50+00:00

Need your feedback on the below code – public static void main(String[] args) {

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Need your feedback on the below code –

public static void main(String[] args) {
try {
        throw new OutOfMemoryError();
    } catch (Exception e) {
        System.out.println("Inside catch");
    } catch (Throwable t){
        System.out.println("Inside catch throwable");
    }finally {
        System.out.println("Inside finally");
    }
}

Here I am throwing an OutOfMemoryError object (using new operator) from try clause & catching Throwable object. So I get the output “Inside catch throwable” & “Inside finally”. But since we are throwing OutofMemError shouldn’t the code exit (i.e. without going to Throwable & finally)? In actual practical project, if we get OutOfMemoryError, the application just exits… why this difference?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-02T03:05:51+00:00Added an answer on June 2, 2026 at 3:05 am

    In general, Errors can be caught too (unless they crash the VM or something), and Java 6 onwards allows catching OutOfMemoryError.

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