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Home/ Questions/Q 8089879
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T19:32:56+00:00 2026-06-05T19:32:56+00:00

new here and new to jQuery. I’ve searched for an answer to my question/

  • 0

new here and new to jQuery. I’ve searched for an answer to my question/ problem without success, so here I come. I’m having problems with this code:

<p>Hello.</p>
<p>Good bye.</p>
<p>Ciao!</p>
<script>
jQuery('p').mouseover(
    function() {
        jQuery(this).css({backgroundColor:'red'});
    }
);
jQuery('p').mouseout(
    function() {
        myElement = jQuery(this);
        setTimeout(function(){
            color = ['red','green','blue','orange'];
            myElement.css({backgroundColor:color[Math.round(Math.random()*3)]});
        }, 1000
        )
    }
);
</script>

The thing is that if we move the cursor over a new paragraph before the last setTimeout function has been executed, then both the first and the second setTimeout functions will act upon the last affected paragraph. For example:

a) Move the cursor over/out a paragraph. Before the setTimeout function associated with the mouseout event is executed,

b) move the cursor over/out a different paragraph. Now the setTimeout function

myElement.css({backgroundColor:color[Math.round(Math.random()*3)]});

will select TWICE consecutively a background color for the second paragraph, and none for the first one. I’ve tried to associate two different vars (myElementOne and myElementTwo) with the jQuery(this) value to no avail. I would appreciate greatly some help. Thanks.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-05T19:32:58+00:00Added an answer on June 5, 2026 at 7:32 pm

    The problem is that your myElement variable is defined in the global scope, and each mouseout execution overwrites the previous value of it.

    If you defined myElement with var myElement = jQuery(this);, myElement will be defined only in the scope of the current mouseout event – and will affect only that element in the timeout callback.

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