Question

New to C, I have this function:

void getNum(int *n) {
  scanf("%d", &n);
}

And in main:

int main() {
  int someNum;
  getNum(&someNum);
  return 0;
}

Where exactly does the ‘int **’ part of this error come from, and are there other issues with how I’m passing things around?

Answer 1

The only problem is passing &n to scanf: n is already a pointer, and so your scanf call is passing a pointer to that pointer, hence the warning.

Use: scanf("%d", n);