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Home/ Questions/Q 4563880
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T18:25:21+00:00 2026-05-21T18:25:21+00:00

New to Django so could be totally wrong in my methodology. I have a

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New to Django so could be totally wrong in my methodology.

I have a block of complex HTML that I reuse in several parts of my site, but populated with different data. I want to turn this into a block I can put anywhere.

I read up on inclusion tags and defined it like this:

from django import template
register = template.Library()

@register.inclusion_tag('release_widget.html')
def release_widget(releases):
    return {'release_list': releases}   

Then when I use it in my templates:

{% load release_widget %}
{% release_widget release_list %}

This works. My issue is that inside the release_widget.html file I lose access to my MEDIA_URL variable which defines where to find my image assets. I assume this is because the context isn’t being passed through?

I looked at the takes_context=True parameter but couldn’t figure it out – it looks like this doesn’t take a variable anymore, which doesn’t work for me – I need to be able to pass a different dictionary each time I include the block.

Is there a better way of doing this? Should I even be using MEDIA_URL at all? I can’t just use absolute paths as my site structure is like site.com/article/something/123 and assets are in site.com/assets/ and I don’t want ../ everywhere.

thanks,
Matt

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  1. Editorial Team
    Editorial Team
    2026-05-21T18:25:21+00:00Added an answer on May 21, 2026 at 6:25 pm

    takes_context is the right way to go. I don’t know why you say it doesn’t take a variable: it does, it just takes the context dictionary as an additional (initial) parameter. So the tag looks like this:

    @register.inclusion_tag('release_widget.html', takes_context=True)
    def release_widget(context, releases):
        return {'MEDIA_URL': context['MEDIA_URL'], 'release_list': releases}   
    
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