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Home/ Questions/Q 7403981
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T05:11:23+00:00 2026-05-29T05:11:23+00:00

new with javascript here. I have a simple form that takes what the user

  • 0

new with javascript here. I have a simple form that takes what the user submits and puts it into an array. When a specific word is submitted, a prompt comes up with a random value from the array. The problem I think I’m having here is that things aren’t actually being pushed into the array, as the prompt will return undefined.

var res_array = [];
var restaurant = document.getElementById("restaurants");
var rand = res_array[Math.floor(Math.random() * res_array.length)];

function submit_res(){
    if (restaurants.value !="end" && restaurants.value !="finish") {
        alert('It got pushed');
        res_array.push(restaurant);
        return true;
    } else {
        alert('Selected restaurant: ' + rand);
    }
}

Now here is the fixed up one —

var res_array = [];

function submit_res(){
var restaurant = document.getElementById("restaurants");

if (restaurants.value !="end" && restaurants.value !="finish") {
    res_array.push(restaurant.value);
} else {
    var random_res = res_array[Math.floor(Math.random() * res_array.length)];
    alert('Selected restaurant: ' + random_res);
}

return false;
}

HTML parts:

<form>
    Restaurants: <input type="text" id="restaurants" name="restaurants" />
    <input type="submit" value="Submit" onClick="return submit_res()"/>
</form>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-29T05:11:24+00:00Added an answer on May 29, 2026 at 5:11 am

    Things are being pushed into the array, but they’re not taken out again.

    The snippet res_array[Math.floor(Math.random() * res_array.length)]; is executed only once, before the user submits any values. res_array is empty at this time, so taking a random element from it results in undefined. This is what is prompted.

    The solution is to move var rand = res_array[...]; into the else {} clause.

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