Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 3663052
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 19, 20262026-05-19T01:29:11+00:00 2026-05-19T01:29:11+00:00

Newbie at Python and maybe I’m not stating the question right, but how do

  • 0

Newbie at Python and maybe I’m not stating the question right, but how do I cast a passed arg to string in python?

Here is what I’m trying:

#!/usr/bin/python
# Python Wrapper to Call XMLRPC service

import xmlrpclib
import sys  

# Set the Server
servAddr = "http://127.0.0.1/xmlrpc.server.php"

# Start the Client
client = xmlrpclib.ServerProxy(servAddr)

for arg in sys.argv:
    id = str(arg)
    print client.service.setId(id) # Throws long error
    # print client.service.setId('123') # Hard coded works
    #print arg # prints the id passed
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-19T01:29:12+00:00Added an answer on May 19, 2026 at 1:29 am

    The values from sys.argv already are strings. I think the problem is that you are passing sys.argv[0] which is the script name. Try this:

    for arg in sys.argv[1:]:
        print client.service.setId(arg)
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I'm newbie in Python, but this question is not a homework (actually this code
I am Python newbie, so maybe don't knew if this is obvious or not.
Here's a bit of a newbie Python question about instance variables. Consider the following
Python newbie here, running 2.7. I am trying to create a program that uses
I am not a total newbie but I am trying to install modules for
Python newbie here. I'm trying to package a console app following this doc .
Python newbie here. I'm trying to create a black jack game in which the
Python newbie here. I was trying to troubleshoot an issue with writing a csv
Newbie to python here, I am trying to use an integer as an argument
I'm newbie in Python. I can't understand why this code does not work: reOptions

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.