Question

Newbie python here. How can I break out of the second while loop if a user selects “Q” for “Quit?”
If I hit “m,” it goes to the main menu and there I can quit hitting the “Q” key.

while loop == 1:
    choice = main_menu()

    if choice == "1":
        os.system("clear")

        while loop == 1:
            choice = app_menu()

            if choice == "1":
                source = '%s/%s/external' % (app_help_path,app_version_10)
                target = '%s/%s' % (target_app_help_path,app_version_10)

            elif choice == "2":
                source = '%s/%s/external' % (app_help_path,app_version_8)
                target = '%s/%s' % (target_app_help_path,app_version_8)
            elif choice.lower() == "m":
                break
                loop = 0
            elif choice.lower() == "q":
                break
                loop = 0
            sendfiles(source, target)

    # Internal files

    elif choice == "q":
        loop = 0

App menu method:

def app_menu()
    print "Select APP version"
    print "-------------------"
    print "1) 11"
    print "2) 10"
    print "3) 8"
    print "m) Main Menu"
    print "q) Quit"
    print
    return raw_input("Select an option: ")

Answer 1

You nearly have it; you just need to swap these two lines.

elif choice.lower() == "m":
    break
    loop = 0

elif choice.lower() == "m":
     loop = 0
     break

You break out of the nested loop before setting loop. 🙂