Question

newbie question,I have the following code where I need to match the data in variable gerrit with the list gerrit_refs and get the corresponding match and save in a variable,how can I do that?

'''
gerrit_refs:
refs/changes/89/202089/4
refs/changes/39/205739/2
refs/changes/94/195594/6
refs/changes/90/202090/4
refs/changes/92/202092/4
'''

def main ():
    gerrit=205739
    with open('gerrit_refs.txt', 'r') as f:
        # Here we make a list of refs based on the file
        gerrit_refs = [line.strip() for line in f]
    match = None
    for ref in gerrit_refs:
        if gerrit in ref:
            match = ref
            print match
            break

if __name__ == '__main__':
    main()

Error:-

TypeError: ‘in ‘ requires string as left operand, not in

Answer 1

Filter out matching lines in your list comprehension:

def main ():
    gerrit = 205739
    gerrit_str = str(gerrit)
    with open('gerrit_refs.txt', 'rb') as f:
        # Here we make a list of refs based on the file
        gerrit_refs = [line.strip() for line in f if gerrit_str in line]

    if gerrit_refs:
        # At least one match was found.
        print gerrit_refs

Note the need to change the gerrit search variable to a string. The in operator doesn’t work with mixed variables.

This will work if there are multiple references as it returns a list. If you just want to grab the first match, then simply extract the first item:

if gerrit_refs:
    print "First match:", gerrit_refs[0]