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Home/ Questions/Q 6724969
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T09:45:05+00:00 2026-05-26T09:45:05+00:00

No but in all seriousness, What i’m trying to do is make it so

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enter image description here

No but in all seriousness, What i’m trying to do is make it so that the selection made by the user in the first spinner dictates the options available in the second.

I’m a little confused as to how to handle this. I’m thinking it would require some sort of listener since the selections could be changed at any time.

As an example lets say I had 2 spinners, the first has options “even numbers” and “odd numbers”. If the user selects even numbers the second spinner displays options “2”, “4”, and “6”. If the user selects odd numbers “1”, “3”, and “5” are selected.

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  1. Editorial Team
    Editorial Team
    2026-05-26T09:45:06+00:00Added an answer on May 26, 2026 at 9:45 am

    Exactly, you need to assign a listener for the first spinner in you example. Check out this thread to check how to do that. In the onItemSelected() callback, you need to modify the contents of the second spinner accordingly. That is, modify the adapter assigned to it.

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