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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T11:10:24+00:00 2026-05-20T11:10:24+00:00

Normally one would build a related model instance through its parent object: @child =

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Normally one would build a related model instance through its parent object:

@child = @parent.children.build(params[:child])

But when we’re using STI and we want to do this while at the same time building it as one of the subclasses the syntax seems to break down. This is the best way to do it as far as I can tell (ignore the security problems around not checking the type against an approved list):

@child = params[:type].classify.constantize.new(params[params[:type]])
@child.parent = @parent

Is this the best way to go about it? I’m using a single controller to build all the different subclass types so I need to supply the type as a parameter.

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  1. Editorial Team
    Editorial Team
    2026-05-20T11:10:24+00:00Added an answer on May 20, 2026 at 11:10 am

    I usually use this trick:

    class BaseModel < ActiveRecord::Base
    
    private
      # this will enable you to set the type field 
      def attributes_protected_by_default
        super - [self.class.inheritance_column]
      end
    end
    

    Now in your controller:

    @parent.children.build(params[:base_model])
    

    Make sure params[:base_model] hash has a field called type. I usually add a hidden form field to store the type.

    Make sure you add the relevant checks to ensure the correct sub types are created.

    Note : This trick will not work in Rails 3.

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