Question

Not a question I want to ask but I really need another pair of eyes on this one as it must be something silly I am missing.

I have used this same script previously so I’ve no idea what’s going wrong.

This is the frnt end code: http://jsfiddle.net/fU3Q3/1/

And the backend PHP is:

<?php 
require("../db.php");

// get the posted values
$email=$_POST['email'];
$password=$_POST['password'];

// now validating the username and password
$sql="SELECT * FROM admin WHERE email='".$email."'";
$result=mysql_query($sql) or die ("No such username exists!");
$row=mysql_fetch_array($result);

// if username exists
if(mysql_num_rows($result)>0)
{
// compare the password
if(strcmp($row['password'],$password)==0)
{
    echo "yes";
    // set the session from here
    $_SESSION['email']=$email; 
}
else
    echo "no"; 
}
else
echo "no"; // invalid Login
?>

Using firebug, the url that is sent to ajax-login.php seems to be email=&password=&rand=0.636999888626322 where obviously the bit on the end is the random number.

Any help is much appreciated.

Martin

Answer 1

$.post("ajax-login.php",{ email:$("input#email").val(),password:$("input#password").val
(),rand:Math.random() } ,function(data)

you have 2 id’s of the same type, a div id of email, a input id of email for example, you can not call #email as it will stop at the first occurance

For further explanation… id’s without associated class names are considered unique, only 1 id can be used however if you have:

<div class='content' id='email'>
<input class='content' id='email'>

you can call these in jquery by using following examples:

formal declaration, type > classname ‘.’ > id ‘#’

$("div.content#email");
$("input.content#email");

and this will not work without matching the first tag

$(".content#email");
$(".content#email");