Question

Not entirely sure how to adequately title this problem, but it entails a need to loop through any array nested within array, of which may also be an element of any other array – and so forth. Initially, I thought it was required for one to tag which arrays haven’t yet been looped and which have, to loop through the “base” array completely (albeit it was learned this isn’t needed and that PHP somehow does this arbitrarily). The problem seems a little peculiar – the function will find the value nested in the array anywhere if the conditional claus for testing if the value isn’t found is omitted, and vice versa. Anyway, the function is as followed:

function loop($arr, $find) {
  for($i=0;$i<count($arr);$i++) {
    if($arr[$i] == $find) {
      print "Found $find";
      return true;
    } else {
      if(is_array($arr[$i])) {
         $this->loop($arr[$i], $find);
      } else {
         print "Couldn't find $find";
         return false;
      }
    }
   }
 }

Answer 1

Perhaps you should change your code to something like:

var $found = false;
function loop($arr, $find) {
  foreach($arr as $k=>$v){
    if($find==$v){
      $this->found = true;
    }elseif(is_array($v)){
      $this->loop($v, $find);
    }
  }
  return $this->found;
}