Question

Not even how to word this question: I have a table that looks like this:

select * from tblServiceUsers
ORDER By ServiceID

0   B88230BB-4943-4C10-AB0E-8ABB88A357A3
0   5653C943-7F9A-4746-B2A3-1160E9204A7E
0   08678EE7-49A7-4F63-BC39-CFCCE2C9AD65
1   B88230BB-4943-4C10-AB0E-8ABB88A357A3
1   5653C943-7F9A-4746-B2A3-1160E9204A7E
2   B88230BB-4943-4C10-AB0E-8ABB88A357A3
2   5653C943-7F9A-4746-B2A3-1160E9204A7E

And I need a query that only returns the top (or first) userid that matches a serviceID.
For example, I just want 1 UserID to be displayed for each ServiceID. Such as the following:

0   B88230BB-4943-4C10-AB0E-8ABB88A357A3
1   B88230BB-4943-4C10-AB0E-8ABB88A357A3
2   B88230BB-4943-4C10-AB0E-8ABB88A357A3

Answer 1

You don’t say which version of SQL server it is, but for MS SQL Server 2005 onwards you can do something like :

 Select SecID, ServiceID, UserID from 
 (
    select ROW_NUMBER() OVER (PARTITION BY ServiceID ORDER BY Secid) AS row_number,
    SecID,
    ServiceID,
    UserID
    From tblSecServiceUsers
 ) 
 tempTable
 where row_number = 1