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Home/ Questions/Q 3406124
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T05:35:23+00:00 2026-05-18T05:35:23+00:00

Not really a question but kind of a challenge.. I have this PHP function

  • 0

Not really a question but kind of a challenge..

I have this PHP function that I always use and now I need it in Javascript.

function formatBytes($bytes, $precision = 0) {
    $units = array('b', 'KB', 'MB', 'GB', 'TB');
    $bytes = max($bytes, 0);
    $pow = floor(($bytes ? log($bytes) : 0) / log(1024));
    $pow = min($pow, count($units) - 1);
    $bytes /= pow(1024, $pow);
    return round($bytes, $precision) . ' ' . $units[$pow];
}

EDIT: Thanks to the replies I came up with something shorter, but without precision (let me know if you have some second thoughts)

function format_bytes(size){
    var base = Math.log(size) / Math.log(1024);
    var suffixes = ['b', 'KB', 'MB', 'GB', 'TB' , 'PB' , 'EB'];
    return Math.round(Math.pow(1024, base - Math.floor(base)), 0) + ' ' + suffixes[Math.floor(base)];
}
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  1. Editorial Team
    Editorial Team
    2026-05-18T05:35:23+00:00Added an answer on May 18, 2026 at 5:35 am

    Tested:

    function formatBytes(bytes, precision)
    {
        var units = ['b', 'KB', 'MB', 'GB', 'TB'];
        bytes = Math.max(bytes, 0);
        var pwr = Math.floor((bytes ? Math.log(bytes) : 0) / Math.log(1024));
        pwr = Math.min(pwr, units.length - 1);
        bytes /= Math.pow(1024, pwr);
        return Math.round(bytes, precision) + ' ' + units[pwr];
    }
    
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