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Home/ Questions/Q 6816855
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T20:58:33+00:00 2026-05-26T20:58:33+00:00

Not really sure how to phrase this question so it’s generic enough. (and will

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Not really sure how to phrase this question so it’s generic enough. (and will rephrase, after I know what I’m asking). The problem, I believe deals with variables in a JQuery .find() function.

Problem: you can wrap $() around an array of DOM elements, or around a jQuery object, but not around an array of jQuery objects

The best I can do, at this time, is provide an example here

The problem code in the previous fiddle, is here:

////////////////Neither of the following works////////////////
//nodelevel = nodesWithMinuses.find('div.node.level' + levelnumber);
  nodelevel = $(nodesWithMinuses).find('div.node.level' + levelnumber);
////////////////Neither of the previous works////////////////
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  1. Editorial Team
    Editorial Team
    2026-05-26T20:58:34+00:00Added an answer on May 26, 2026 at 8:58 pm

    Apparently you can wrap $() around an array of DOM elements, or around a jQuery object, but not around an array of jQuery objects.

    Try changing this line:

    var nodeWithMinus = thisplusminus.parent().parent();
    

    to this:

    var nodeWithMinus = thisplusminus.parent().parent()[0];
    

    This will extract the DOM element and turn nodesWithMinuses into an array of DOM elements.

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