Question

Not sure how to title my question… lol.

Below is what i am needing.

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Values in my database look like the following: test_example-1, test_example-2, test_example-TD-1

The values can vary in length, “test_example-” is just an example, some of the values will have varying names.

When i perform a query to grab all the values that look like this “test_example-” i get everything, because i am using the wild card value this way “test_example-%”. However, i do not want the “test_example-TD-1” in the result. I only want the NON-TD values. So, how can i get all the “test_example-” without getting stuff that has more than just a single digit integer after the “-“.

A value in the database will not have anymore than a single digit number (0-9) after the “-“. So basically i need a query that searches for values that would look like this “test_example-[0-9]”.

How can i do that? If this is confusing and needs clarification, please let me know. Thanks!

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Here is the exact query that i am doing to ease some confusion:

SELECT MAC, NAME FROM HOST WHERE NAME LIKE (SELECT CONCAT(LEFT(NAME, LENGTH(NAME)-1), "%") FROM HOST WHERE MAC="some mac address");

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Here is the working result ( thanks to swati ):

SELECT MAC, NAME FROM HOST WHERE NAME REGEXP CONCAT(LEFT(NAME, LENGTH(NAME)-1), "[0-9]+") AND MAC="some mac address";

Answer 1

SELECT * FROM `foo` WHERE `value` REGEXP "test_example-[:digit:]+"

That should work for test_example-[0-9]. More on Character Classes and REGEXP

With your given query, it would be:

SELECT MAC, NAME FROM HOST WHERE NAME REGEXP CONCAT(LEFT(NAME, LENGTH(NAME)-1), "[0-9]+") AND MAC="some mac address"

Note there is an error in your posted query – you have two WHERE clauses.