Question

Not sure why but I am not getting anything back from the json call. I echo’ed the content out and pasted to my url bar of my browser and it works. Is there some sort of domain problem here that I need to address?

$connect = open_db();
$result = mysql_query("SELECT search_id, search_term FROM search WHERE search_poi_id IS NULL");
while($row = mysql_fetch_assoc($result)){
    $call = "http://maps.google.com/maps/api/geocode/json?address=".$row["search_term"]."&sensor=false";
    $json = file_get_contents($call);
    print_r($json);
}
close_db($connect);

Answer 1

file_get_contents() may not always work for external URLs. From php.net:

A URL can be used as a filename with this function if the fopen wrappers have been enabled. See fopen() for more details on how to specify the filename. See the Supported Protocols and Wrappers for links to information about what abilities the various wrappers have, notes on their usage, and information on any predefined variables they may provide.