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Home/ Questions/Q 742641
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T08:46:16+00:00 2026-05-14T08:46:16+00:00

Not sure why I’m getting this error. I have the following: int* arr =

  • 0

Not sure why I’m getting this error. I have the following:

int* arr = new int[25];

int* foo(){
   int* i;
   cout << "Enter an integer:";
   cin >> *i;
   return i;
}

void test(int** myInt){
   *myInt = foo();
}

This call here is where I get the error:

test(arr[0]);   //here i get invalid conversion from int to int**
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  1. Editorial Team
    Editorial Team
    2026-05-14T08:46:16+00:00Added an answer on May 14, 2026 at 8:46 am

    The way you’ve written it, test takes a pointer to a pointer to an int, but arr[0] is just an int.

    However, in foo you are prompting for an int, but reading into a location that is the value of an uninitialized pointer. I’d have thought you want foo to read and return and int.

    E.g.

    int foo() {
       int i;
       cout << "Enter an integer:";
       cin >> i;
       return i;
    }
    

    In this case it would make sense for test to take a pointer to an int (i.e. void test(int* myInt)).

    Then you could pass it a pointer to one of the int that you dynamically allocate.

    test(&arr[0]);
    
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