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Home/ Questions/Q 7631615
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T06:23:57+00:00 2026-05-31T06:23:57+00:00

Note: You may be able to help me with this just by directing me

  • 0

Note: You may be able to help me with this just by directing me to a place that explains well how to interface with web services. But help on this specific problem would be greatly appreciated!

I’m having a really hard time understanding how OAuth works. I’m trying to develop a desktop application which will upload a bunch of videos to accounts on Vimeo. I’ve tried tinkering a bit with the Scribe API and its examples. Scribe doesn’t have a Vimeo example unfortunately, so I’ve been trying to alter the Facebook example to make it work for Vimeo. There’s very little information on how this all works (that I’ve been able to 1: find, 2: understand). Here’s what I have as far as code and errors:

public class VimeoTest
{
  private static final String NETWORK_NAME = "Vimeo";
  private static final Token EMPTY_TOKEN = null;

  public static void main(String[] args)
  {
    // Replace these with your own api key and secret
    String apiKey = "MYAPIKEY";
    String apiSecret = "MYAPISECRET";
    OAuthService service = new ServiceBuilder()
                                  .provider(VimeoApi.class)
                                  .apiKey(apiKey)
                                  .apiSecret(apiSecret)
                                  .build();
    Scanner in = new Scanner(System.in);

    System.out.println("=== " + NETWORK_NAME + "'s OAuth Workflow ===");
    System.out.println();
    OAuthRequest orequest = new OAuthRequest(Verb.GET, "http://vimeo.com/api/rest/v2");
    orequest.addQuerystringParameter("method", "vimeo.test.null");
    Response send = orequest.send();
    System.out.println(send.getBody());

    // Obtain the Authorization URL
    System.out.println("Fetching the Authorization URL...");
    Token requestToken = service.getRequestToken();

    //Breaks on the line above.
    //But I think it's because the orequest.send() returned a 100 error code

    String authorizationUrl = service.getAuthorizationUrl(requestToken);
    System.out.println("Got the Authorization URL!");
    System.out.println("Now go and authorize Scribe here:");

    //I do NOT want to have to do this. Is there any other way I can have this authorize without going to a web browser to do this?

    System.out.println(authorizationUrl);
    System.out.println("And paste the authorization code here");
    System.out.print(">>");
    Verifier verifier = new Verifier(in.nextLine());
    System.out.println();

Here’s the output and Error:

=== Vimeo's OAuth Workflow ===

1.0
<?xml version="1.0" encoding="utf-8"?>
<rsp generated_in="0.0069" stat="fail">
  <err code="100" expl="The API key passed was not valid" msg="Invalid API Key" />
</rsp>
Fetching the Authorization URL...
Exception in thread "main" java.lang.NoClassDefFoundError: org/apache/commons/codec/binary/Base64
    at org.scribe.services.HMACSha1SignatureService.doSign(HMACSha1SignatureService.java:47)
    at org.scribe.services.HMACSha1SignatureService.getSignature(HMACSha1SignatureService.java:33)
    at org.scribe.oauth.OAuth10aServiceImpl.getSignature(OAuth10aServiceImpl.java:118)
    at org.scribe.oauth.OAuth10aServiceImpl.addOAuthParams(OAuth10aServiceImpl.java:63)
    at org.scribe.oauth.OAuth10aServiceImpl.getRequestToken(OAuth10aServiceImpl.java:43)
    at autouploadermodel.VimeoTest.main(VimeoTest.java:38)
Caused by: java.lang.ClassNotFoundException: org.apache.commons.codec.binary.Base64
    at java.net.URLClassLoader$1.run(URLClassLoader.java:366)
    at java.net.URLClassLoader$1.run(URLClassLoader.java:355)
    at java.security.AccessController.doPrivileged(Native Method)
    at java.net.URLClassLoader.findClass(URLClassLoader.java:354)
    at java.lang.ClassLoader.loadClass(ClassLoader.java:423)
    at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:308)
    at java.lang.ClassLoader.loadClass(ClassLoader.java:356)
    ... 6 more
Java Result: 1

Anyway, I’ll bet this is really simple, but I just don’t understand how to interface with web services. Thanks for any help!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T06:23:59+00:00Added an answer on May 31, 2026 at 6:23 am

    You need to include apache commons codec on your classpath

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