Question

Novice question: how would you write this in racket?

10x - 6 = 3x + 7

I am having a hard time trying to figure out where would I put the = 3x + 7.

Answer 1

Try this:

(= (- (* 10 x) 6)
   (+ (*  3 x) 7))

Of course, assuming that a value has been assigned previously to the x variable. Now, if the expression is to be evaluated as part of a function (as suggested by the title), then do this:

(define (test x)
  (= (- (* 10 x) 6)
     (+ (*  3 x) 7)))