Question

Now I know that just putting an array with 16 digits is too much for arrays and it will give an answer but for a cybersecurity class I wish to gain access to routers around my neighborhood.

I won’t mess with them but I serve to prove a point and all the routers are the same thanks to living in the middle of nowhere. They are 16 digits long.

So can anyone help me solve how I would get 16 digits together and create it all in a txt file?

What I want to do is create a new file, and then make things that would make it so that it is a dictionary-type in that it has every number of 0000000000000000 -> 9999999999999999.

The creating of the file is no problem for me, but how would I create this dictionary of numbers with a 16 number sequence?

Edit: I thought about splitting it up into 4 4 digit things but I am unsure how I would make sure that they are a) not the same number as before and b), make a space after the sixteenth digit is in.

Answer 1

First, your number (99…9) has 16 digits. In term of data type in Java, it about 53 bit (<64 bit so far) so it is an long

But, assume that each number is 64 bit.
So the file size could be size = (99..99) (number) * 64 (bit per number) = 73k Tera Byte (impossible to store in a text file in normal way!)

So you should consider another way (?)

Furthermore, you can not declare long l = 999999999999999; because the compiler got the error (integer number to large), but this works: long l = Long.parseLong("9999999999999999");

Hope this can help you !

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Edit: Declare by long l = 9999999999999999999l; (l can be both upper and lower case, thanks @Tom)