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Home/ Questions/Q 3242104
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T18:16:34+00:00 2026-05-17T18:16:34+00:00

NSPredicate *predicate = [NSPredicate predicateWithFormat:@List.name == ‘kristof\\’s list’]; Works as expected. However I want

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NSPredicate *predicate = [NSPredicate predicateWithFormat:@"List.name == 'kristof\\'s list'"]; 

Works as expected.
However I want do something like this:

    NSString *listName = [[[detailItem valueForKey:@"name"] description] stringByReplacingOccurrencesOfString:@"'" withString:@"\\'"];
NSPredicate *predicate = [NSPredicate predicateWithFormat:@"List.name == '%@'", listName];

It returns nothing, even if I try this:

NSPredicate *predicate = [NSPredicate predicateWithFormat:@"List.name == '%@'", @"kristof\\'s list"];

It remains empty.
Any ideas ?

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  1. Editorial Team
    Editorial Team
    2026-05-17T18:16:34+00:00Added an answer on May 17, 2026 at 6:16 pm

    The behaviour of [NSString stringWithFormat] and [NSPredicate predicateWithFormat] are different. NSString performs the substitution on creation, whereas NSPredicate on evaluation. Your single quotes are preventing the substitution.

    For more take a look at the CocoaDev Forums.

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