Question

Object instanceof Object
true
Object instanceof Function
true
Function instanceof Object
true
Function instanceof Function
true

so if Function is an Object and the Object is a Function how come

Function === Object and Function == Object are false?

I do understand that checking the instance of an object is not the same as comparison. So the question here is the fuzziness in the case where if two objects (which are actually types) are instances of each other, shouldn’t the types be the same?

Note: Object is not an instance of a Number or an Array just an instance of Function.

Answer 1

From JavaScript Prototypal Inheritance:

Quite everything, in JavaScript, inherits from Object. We could say
that Object is the super class, or better, the super constructor, of
every variable and that everything is an instanceof Object. The Object
constructor is a Function, but a Function is an instanceof Object.
This means that these assertions are always true:

(Object instanceof Function) === (Function instanceof Object)

Above example is true because Object is a constructor, and a constructor in JavaScript is always a Function. At the same
time, every Function has its own prototype, and a prototype always
starts its inheritance from Object.prototype. The Function
constructor, is a Function itself, and the function prototype is a
function(){};

(Function.prototype instanceof Object) === (function(){} instanceof Object)