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Home/ Questions/Q 7729805
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T06:03:52+00:00 2026-06-01T06:03:52+00:00

object ReassignTest extends App { class X(var i : Int) def x = new

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object ReassignTest extends App {
  class X(var i : Int)

  def x = new X(10)
  x.i = 20  // this line compiles

  println(x.i)  // this prints out 10 instead of 20, why?
}

So how would I created a setter for parameter i

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T06:03:54+00:00Added an answer on June 1, 2026 at 6:03 am

    You defined x to be a method which returns a new X everytime you ‘call’ it.

    def x = new X(10) //define a function 'x' which returns a new 'X'
    x.i = 20  //create a new X and set i to 20
    
    println(x.i) //create a new X and print the value of i (10)
    

    Define x to be a value instead, and the behavior will be as you expect

    val x = new X(10) //define a value 'x' which is equal to a new 'X'
    x.i = 20  //set 'i' to be to 20 on the value 'x' defined above 
    
    println(x.i) //print the current value of the variable i defined on the value 'x'
    
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