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Home/ Questions/Q 8683831
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T22:08:44+00:00 2026-06-12T22:08:44+00:00

observe the code if($line[$x]==1 and !empty($cat_ids[$x])) array_push($cat1,$cat_ids[$x]); elseif($line[$x]==1 and $cat_ids[$x]=) array_push($cat1,id not allocated); $line[$x]

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observe the code

if($line[$x]==1 and !empty($cat_ids[$x]))
    array_push($cat1,$cat_ids[$x]);
    elseif($line[$x]==1 and $cat_ids[$x]="")
    array_push($cat1,"id not allocated");

$line[$x] contains 1 and $cat_ids[$x] contains the id.

when the id is empty, i want to push “id not allocated” into the array at that particular $line[$x]. Please help me…

the code i written is skipping the empty field instead of printing ‘id not allocated’

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  1. Editorial Team
    Editorial Team
    2026-06-12T22:08:45+00:00Added an answer on June 12, 2026 at 10:08 pm

    Try changing

    elseif($line[$x]==1 and $cat_ids[$x]="")
    

    to

    elseif($line[$x]==1 and $cat_ids[$x]=="")
    

    as $cat_ids[$x]="" statement will assign the value null to $cat_ids[$x]

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