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Home/ Questions/Q 555649
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T11:50:12+00:00 2026-05-13T11:50:12+00:00

Occasionally, Spring can’t figure out what type a value should be. This happens when

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Occasionally, Spring can’t figure out what type a “value” should be. This happens when the property or constructor is of type “java.lang.Object”. In these cases, Spring defaults to “java.lang.String”. Sometimes this isn’t the right choice, for example when using:

<jee:jndi-lookup id="test" jndi-name="java:comp/env/test" 
   default-value="10" expected-type="java.lang.Integer"/>

If the lookup fails and it has to fall back to the default-value, there’s a type mismatch. So, instead, this needs to be done:

  <bean id="test" class="org.springframework.jndi.JndiObjectFactoryBean">
    <property name="jndiName" value="java:comp/env/test" />
    <property name="defaultObject">
      <bean class="java.lang.Integer">
        <constructor-arg value="10" />
      </bean>
    </property>
  </bean>

which is somewhat verbose, especially if there are lots of them. Is there some handy way to declare an Integer / Long / Double / Float / String literal without having to use this format:

      <bean class="java.lang.Integer">
        <constructor-arg value="10" />
      </bean>
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  1. Editorial Team
    Editorial Team
    2026-05-13T11:50:12+00:00Added an answer on May 13, 2026 at 11:50 am

    Since Spring 3.0, you can use Spring Expression Language: #{new Integer(10)}

    <jee:jndi-lookup id="test" jndi-name="java:comp/env/test" 
        default-value="#{new Integer(10)}" expected-type="java.lang.Integer"/>
    
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