Question

>>> odd,even=[ ],[ ]
>>> [even.append(x) if x%2==0 else odd.append(x) for x in range(51)]
[None, None, None, None, None, None, None, None, None, None, None, None, None, None, None, None, None, None, None, None, None, None, None, None, None, None, None, None, None, None, None, None, None, None, None, None, None, None, None, None, None, None, None, None, None, None, None, None, None, None, None]
>>> odd
[1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31, 33, 35, 37, 39, 41, 43, 45, 47, 49]

my question: is it possible to separate the odd and even numbers in the list comprehension statement even without declaring the odd, even = [], [] at the beginning?

Answer 1

Try this version: for me elegnat,compact and fine to understand

even,odd = [],[]
for x in range(51): x%2 and even.append(x) or odd.append(x)