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Home/ Questions/Q 414959
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T18:20:01+00:00 2026-05-12T18:20:01+00:00

Often when working with templates, you end up with something like: template <T> class

  • 0

Often when working with templates, you end up with something like:

template <T>
class the_class
{
public:
   // types
   typedef T value_type;
   typedef const value_type const_value_type;

   typedef value_type& reference;
   typedef const_value_type& const_reference;

   typedef value_type* pointer;
   typedef const_value_type* const_pointer;

   ...
};

This is lot’s of the same stuff, though, copied to lots of different templated classes. Is it worthwhile to create something like:

// template_types.h

#define TEMPLATE_TYPES(T) \
       typedef T value_type; \
       typedef const value_type const_value_type; \
       typedef value_type& reference; \
       typedef const_value_type& const_reference; \
       typedef value_type* pointer; \
       typedef const_value_type* const_pointer;

So my class just becomes:

#include "template_types.h"

template <typename T>
class the_class
{
public:
   TEMPLATE_TYPES(T)
   ...
};

This seems cleaner, and avoids duplication when I make other template classes. Is this a good thing? Or should I avoid this and just copy-paste typedefs?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-12T18:20:01+00:00Added an answer on May 12, 2026 at 6:20 pm

    Sure, what you’re doing would work, but it’s kind of old-school. Have you tried to put that stuff into another template class that you could derive from?

    template <typename T>
    class template_defs
    {
    public:
       // types
       typedef T value_type;
       typedef const value_type const_value_type;
       typedef value_type& reference;
       typedef const_value_type& const_reference;
       typedef value_type* pointer;
       typedef const_value_type* const_pointer;
    };
    
    template <typename T>
    class the_class : public template_defs<T>
    ...
    
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