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Home/ Questions/Q 6648461
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T00:39:28+00:00 2026-05-26T00:39:28+00:00

Ok bit of a basic question here but I wanted to know what the

  • 0

Ok bit of a basic question here but I wanted to know what the best way to go about this…

I have a HashSet that I am adding objects to, the .add() method will only add an object if it is not already present. But what I want to do is add ALL objects, then at the end get the following results..

-Number of unique (distinct) objects
-The average frequency of objects

Could someone point me in the right direction?

Thanks in advance

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  1. Editorial Team
    Editorial Team
    2026-05-26T00:39:28+00:00Added an answer on May 26, 2026 at 12:39 am

    HashSet isn’t really suited for keeping track of individual counts but HashMap is nearly perfect.

    import java.util.HashMap;
    import java.util.Map;
    
    public class Count<K, V> extends HashMap<K, V> {
    
        // Counts unique objects
        public void add(K o) {
            int count = this.containsKey(o) ? ((Integer)this.get(o)).intValue() + 1 : 1;
            super.put(o, (V) new Integer(count));
        }
    
        // Demonstration
        public static void main(String[] args) {
    
            Count<Object, Integer> c = new Count<Object, Integer>();
    
            String one = "one";
            String two = "two";
            String six = "six";
    
            c.add(one);
            c.add(two);
            c.add(two);
            c.add(six);
            c.add(six);
            c.add(six);
    
            System.out.println("Number of distinct objects: " + c.size());
    
            System.out.println("Frequency of different objects: ");
    
            for (Map.Entry<Object, Integer> entry : c.entrySet()) {
                System.out.println(entry.getKey() + " - " + entry.getValue());
            }
        }
    }
    

    When run, this standalone snippet outputs

    Number of distinct objects - 3
    Frequency of different objects:
    two - 2
    one - 1
    six - 3
    
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