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Home/ Questions/Q 6550679
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T12:14:42+00:00 2026-05-25T12:14:42+00:00

Ok, have this code here: $search = array(‘{POST}’, ‘{post}’); $replace = $recent[‘body’]; $message =

  • 0

Ok, have this code here:

$search = array('{POST}', '{post}');
$replace = $recent['body'];
$message = str_replace($search, $replace, html_entity_decode($params['post_html']));

$params[post_html'] is a variable that holds the users input with either {POST} or {post} defined, for example could be like this, after it gets decoded ofcourse:

<span class="upperframe">
  <span></span>
</span>
<div class="roundframe dp_control_flow">
{POST}
</div>
<span class="lowerframe">
  <span></span>
</span>

Anyways, the problem I’m facing here is, for some reason, str_replace is ALSO replacing and {POST} or {post} strings within the replace parameter: $recent['body'] This should NOT happen, how can I fix this so that it doesn’t perform a replace on the thing that needs to be replacing {POST} or {post}?

I did not expect this function to do replaces within the replace variable. OUCH. Is there a way around this? Do I have to use a preg_replace instead? If so, can someone help me with a regex for this?

Thanks guys 🙂

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  1. Editorial Team
    Editorial Team
    2026-05-25T12:14:42+00:00Added an answer on May 25, 2026 at 12:14 pm

    use str_ireplace() then you don’t need the array for the search and the issue is solved.

    $recent['body']="*test* {post} *test*";
    $params['post_html']="foo {POST} bar";
    
    
    //$search = array('{POST}', '{post}');
    $search = '{post}';
    $replace = $recent['body'];
    $message = str_ireplace($search, $replace, html_entity_decode($params['post_html']));
    
    echo $message; 
    
    
    //with array
    // foo *test* *test* {post} *test* *test* bar
    
    //without
    //foo *test* {post} *test* bar
    
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