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Home/ Questions/Q 6154255
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T20:14:02+00:00 2026-05-23T20:14:02+00:00

Ok here is some example data and the expected results I would like: 2011-06-26

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Ok here is some example data and the expected results I would like:

  • 2011-06-26 17:07:38-04 <– Start Date
  • 2011-10-01 00:00:00-04 <– Wanted Date
  • 91 <– Duration in days

  • 2011-06-25 20:08:46-04 <– Start Date

  • 2011-09-01 00:00:00-04 <– Wanted Date
  • 62 <– Duration in days

Here are the conditions:

  • If the day the 1st to the 25th, add two months plus how many days until the next first
  • If the day is the 26th till the end of the month, add three months plus how many days until the next first

Here is what I’m trying and I’m close but this seems to be doing a ton of calculations and I wanted to see if I could simplify it:

CASE
    WHEN (((DATE_TRUNC('month', 
        (date_field + INTERVAL '5 DAYS')) + INTERVAL '2 MONTH') - 
        (date_field + INTERVAL '5 DAYS') >= 62) AND 
        ((DATE_TRUNC('month', (date_field + INTERVAL '5 DAYS')) + 
        INTERVAL '2 MONTH') - (date_field + INTERVAL '5 DAYS') <= 92))
    THEN (DATE_TRUNC('month', 
        (date_field + INTERVAL '5 DAYS')) + INTERVAL '2 MONTH')
    ELSE (DATE_TRUNC('month', 
        (date_field + INTERVAL '5 DAYS')) + INTERVAL '3 MONTH')
END
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T20:14:02+00:00Added an answer on May 23, 2026 at 8:14 pm
    select 
        case 
            when extract(day from date_field) <= 25 
            then date_trunc('month', date_field + interval '3 months')
            else date_trunc('month', date_field + interval '4 months')
        end
    from t
    
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