Question

Ok here is the deal i am building a messaging system by php,ajax,jquery and mysql i add the new message and i add in 2 rows now what i want to do is to send an ajax request to server and recieve an updated version of the table but sorted So how can i do so

//here i add and call the message the message

function addMsg()     {       //alert(post);         $.get('db.php',$('form').serialize(),            function(data){             getMsg(data);},'html'); } 

function getMsg(data) { alert(data);
$(‘#t1’).append(data); } //php

‘.”.”.$row[‘col’].”.$row[‘col’].”.$row[‘col’].”; } ?>

//Now for sorting //javascript

function sort()     {         $.ajax({           url: 'sort.php',           dataType: 'text',           success: function(data){           $('t1').text(data);               }          });      } 

//php

$result = mysql_query(‘SELECT * FROM table ORDER BY col desc’);

            while($row = mysql_fetch_array($result))            {                 echo '<tbody><tr><td>'.'&#8226;'.'</td><td>'.$row['col'].'</td><td>'.$row['col'].'</td><td></td><td></td><tr><td></td><td colspan='4'>'.$row['col'].'</td></tr></tbody>';             } 

?>

Answer 1

Use ORDER BY when you do the SELECT. Check this: http://dev.mysql.com/doc/refman/5.0/en/sorting-rows.html