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Home/ Questions/Q 4078680
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T17:42:17+00:00 2026-05-20T17:42:17+00:00

Ok I have my main.xml defined like: <LinearLayout android:id=@+id/linearLayout1 android:orientation=vertical android:layout_width=fill_parent android:layout_height=fill_parent xmlns:android=http://schemas.android.com/apk/res/android> <EditText

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Ok I have my main.xml defined like:

<LinearLayout android:id="@+id/linearLayout1" android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent" xmlns:android="http://schemas.android.com/apk/res/android">

    <EditText android:text="EditText" android:id="@+id/editText1" android:layout_width="match_parent" android:layout_height="175px"></EditText>
    <LinearLayout android:layout_height="wrap_content" android:id="@+id/linearLayout2" android:layout_width="match_parent" android:layout_marginLeft="100px">
        <Button android:id="@+id/button1" android:layout_height="wrap_content" android:layout_weight="1" android:layout_width="wrap_content" android:text="@string/btnPrint"></Button>
        <Button android:id="@+id/button2" android:layout_height="wrap_content" android:layout_weight="1" android:layout_width="wrap_content" android:text="@string/btnCancel"></Button>
    </LinearLayout>
</LinearLayout>

I want to be able to update the EditText’s cursor position from code before the call to setContentView(R.layout.main), is this possible? If not, what is the xml attribute for setting the cursor position of an EditText View?

Thanks,

Justin

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-20T17:42:17+00:00Added an answer on May 20, 2026 at 5:42 pm

    You won’t be able to manipulate your view from the java side before your setContentView() call, because findViewById(R.id.yourView) will return null unless the view in question is actually on the screen. Is there a reason you don’t want to do it like this?

    setContentView(R.layout.main);
    EditText et = (EditText)findViewById(R.id.yourEditText);
    et.setSelection(position);
    

    Although the cursor will technically move after its visible, it is going to be so fast that users are unlikely to notice.

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