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Editorial Team
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Asked: 2026-06-13T03:45:16+00:00

Ok I know this has been asked but I feel my situation is a

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Ok I know this has been asked but I feel my situation is a little different and unique. I have my php and html code merged together and it is making a table 9 images long instead of 3 by 3. Also a secondary problem if someone is kind enough to help me out I am looking to format all the pictures to the same size to make the table look better any help is appreciated.

Here is my table file

<?php 
// Get our database connector
require("includes/conn.php");
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
  "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">

<html xmlns="http://www.w3.org/1999/xhtml">

<body>

    <div>

        <?php   
            // Grab the data from our people table
            $sql = "select filename from people LIMIT 9";
            $result = mysql_query($sql) or die ("Could not access DB: " . mysql_error());
            $count = mysql_num_rows(result);
            $i = 0;
            $per_row = 3;
            echo '<table><tr>';

            while ($row = mysql_fetch_assoc($result))
            {

            echo "<td><img src=\"images/" . $row['filename'] . "\" alt=\"\" /><br /></td>";

            if(++$i % $per_row == 0 && $i > 0 && $i < $count) {
                # Close the row
                echo '</tr><tr>';
                }
        }

            for($x = 0; $x < $per_row - $i % $per_row; $x++) {
             echo '<td></td>';
            }
            echo '</tr></table>';


        ?>

    </div>
</body>

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1 Answer

  1. Editorial Team

    You have:

    $count = mysql_num_rows(result);

    instead of:

    $count = mysql_num_rows($result);

    Here’s a working simulation, with an array instead of mysql calls: http://codepad.org/Fyv2mIvS

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