Question

Ok, I spend many time on this, I don’t get what I’m doing wrong.

It seems impossible to get the data in the PHP file.

1. First I call many times “copy” to fill the “result” array.
2. Then, I call the $.ajax method
3. In the process.php $_POST is empty

–> In the PHP $x, $y or $time or not null but not empty.

Edit 2:

Ok – with json_last_error() i saw that it’s my json which is
“Syntax error: malformed”. But i don’t know how to encode it better than what i’m
doing.

So i cheat by adding a stripslashes() on the $_POST.

[{\”x\”:104,\”y\”:218,\”timestamp\”:1349476537434},{\”x\”:90,\”y\”:202,\”timestamp\”:1349476537469},{\”x\”:82,\”y\”:192,\”timestamp\”:1349476537487},{\”x\”:71,\”y\”:177,\”timestamp\”:1349476537514},{\”x\”:68,\”y\”:174,\”timestamp\”:1349476537568},{\”x\”:68,\”y\”:173,\”timestamp\”:1349476537801},{\”x\”:68,\”y\”:174,\”timestamp\”:1349476538478},{\”x\”:68,\”y\”:175,\”timestamp\”:1349476538512},{\”x\”:68,\”y\”:175,\”timestamp\”:1349476538579},{\”x\”:69,\”y\”:175,\”timestamp\”:1349476538678}]

Edit 1:

The posted data seems to be good (look under), and i finish in the
“success function”.

[{“x”:529,”y”:97,”time”:1349469608703},{“x”:385,”y”:331,”time”:1349469608720},…..]

JS Side – index.php :

<script src="jquery.js"></script>    

results = new Array();

function copy(x, y, time) {
   var o = { 'x': x, 'y': y, 'time': time };
   results.push(o);
}

function save() {
    var encoded_results = JSON.stringify(results);

    $.ajax({
        url: "process.php",
        type: 'POST',
        data: {
            "results" : encoded_results 
        },

        success: function(data, status, xhr) {
           alert(data);
           console.log(data);
           console.log(xhr);
        },      
        error: function (xhr, ajaxOptions, thrownError) {
            alert(xhr.status);
            alert(thrownError);
        }
    });
}

PHP Side – process.php :

if(isset($_POST["results"]))
{
    $result_json = $_POST["results"];
    $JSONArray  = json_decode($result_json, true);

    if($JSONArray !== null)
    { 
        $x = $JSONArray["x"];
        $y = $JSONArray["y"];
        $time = $JSONArray["time"]
    }
}

Answer 1

On the JavaScript side you are posting an array of objects – a list of x / y / time combinations. The PHP side however ignores the list and object part:

$x = $JSONArray["x"];

vs.

$x = $JSONArray[0]->x;

So overall in a loop maybe:

foreach($JSONArray as $triple)
{
    $x=$triple->x;
    $y=$triple->y;
    $time=$triple->time;
}