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Home/ Questions/Q 827443
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T03:34:32+00:00 2026-05-15T03:34:32+00:00

Ok, maybe this isn’t so amazing considering I don’t really understand how the debugger

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Ok, maybe this isn’t so amazing considering I don’t really understand how the debugger works in the first place, let alone Edit and Continue, which is totally amazing.

But I was wondering if anyone knew what the debugger is doing with variable declarations in this scenario. I can be debugging through my code, move the line of execution ahead – past a variables initial declaration and assignment, and the code still runs ok. If it’s a value type it will have it’s default value, for a ref type, null.

So if I create a function that uses a variable before it’s declared it won’t compile, but if I use the debugger to run it that way it will still run without error. Why is this? And is this related to the fact that you can’t put a breakpoint on a declaration?

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  1. Editorial Team
    Editorial Team
    2026-05-15T03:34:33+00:00Added an answer on May 15, 2026 at 3:34 am

    Yes, those declarations are more structural. They’re part of the locals on the stack that are allocated as the method is called. You can’t break on them because they don’t really happen where you write them – they’re not instructions.

    The reason the compiler won’t let you use them before they are declared is mostly for your sanity – you always know to look up for a declaration. Complex scoping of variables within a method would further illustrate this point.

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