Question

OK:

my $login='anybody';
exit if $login ne 'root';

NOT OK: Why doesn’t the following print “error“?

my $login='anybody';
(print "error" && exit) if $login ne 'root';

I know about if (condition) {action}. I just want to know about current problem.

Answer 1

Because what you have written says:

“print the evaluation of the string ‘error’ and the result of the command exit”

You could actually write:

((print "error\n") && exit) if $login ne 'root';

But please don’t. 🙂