Question

Ok so basically what I am trying to do is show a div if MySQL row data is equal to an entered value for example if the user type column says admin-full it needs to show some content.

I am quite new to PHP so I really appreciate your help on this my code is as follows.

<?php

$row_user['type'] = $user_type;

if ($user_type == admin_full)
{
    <!-- START DIV DROPDOWN BOX--> 
  <div class="dropbox">
            <a id="myHeader1" href="javascript:showonlyone('newboxes1');" >show this one only</a>
  </div>   
  <div class="newboxes" id="newboxes1">Div #1</div>
  <!-- END DIV DROPDOWN BOX-->
}
  ?> 

Answer 1

<?php

Like this

<?php
    // you probably have this line wrong. 
    //$row_user['type'] = $user_type; 
    // and you want
    $user_type = $row_user['type'];

    // I am assuming admin_full is not a constant, otherwise remove the single quotes 
    if ($user_type === 'admin_full') 
    {
    ?>
        <!-- START DIV DROPDOWN BOX--> 
            <div class="dropbox">
                <a id="myHeader1" href="javascript:showonlyone('newboxes1');" >show this one only</a>
            </div>   
            <div class="newboxes" id="newboxes1">Div #1</div>
        <!-- END DIV DROPDOWN BOX-->
    <?php
    }
    else {
        ?>

        Oops, what the duce are you doing dude!

        <?php
    }
    ?> 

I am assuming admin_full is not a constant and you wanted a string otherwise replace that line with

if ($user_type == admin_full)