Question

Ok so I am making a roulette game. The random number that the spinner lands on is called ‘figure’. It is a very basic and simple code but it won’t seem to work for me properly.
At the moment you either pick a specific number or choose 1 – 18. I’ve tried many different ways and still no luck. Here is my code. If anyone knows what the problem is please let me know. Thanks:

numbers = ['1', '2', '3'.......'35', '36']

figure = choice(numbers)

d = textinput("Pick bet", "")

if int(figure) > 18 and d == '1-18' or '1 - 18' or '1- 18' or '1 -18':
    pu()
    goto(100,100)
    write("Loser", font = ("Comic Sans MS", 30, "bold"))

elif int(figure) < 19 and d == '1-18' or '1 - 18' or '1- 18' or '1 -18':
    pu()
    goto(10,100)
    write("Well done", font = ("Comic Sans MS", 30, "bold"))


elif int(d) in range(36) and int(figure) == int(d):
    pu()
    goto(100,100)
    write("Well done", font = ("Comic Sans MS", 30, "bold"))

elif int(d) in range(36) and int(figure) != int(d):
    pu()
    goto(100,100)
    write("Loser", font = ("Comic Sans MS", 30, "bold"))

Answer 1

Look at:

if int(figure) > 18 and d == '1-18' or '1 - 18' or '1- 18' or '1 -18':

Here you have several statements that always evaluate to True; each of '1 - 18' or '1- 18' or '1 -18' is a a non-empty string. It doesn’t matter what values int(figure) or d have. This means python sees that line as the equivalent of if something or True.

What you want to do instead is use the in operator to test if your d is part of a list of options:

if int(figure) > 18 and d in ('1-18', '1 - 18', '1- 18', '1 -18'):

The same problem applies to your elif statement.