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Home/ Questions/Q 7583491
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T18:41:28+00:00 2026-05-30T18:41:28+00:00

Ok so I have a class called Dog() which takes two parameters, a string

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Ok so I have a class called Dog() which takes two parameters, a string and an integer.
This class has a method called bark(), which prints a string depending on the integer passed into the Dog() constructor.

I also have a class called Kennel() which creates an array of 5 Dog()s… looks like this:

public class Kennel
{
    Dog[] kennel = new Dog[5];
    public Kennel()
    {
        kennel[0] = new Dog("Harold",1);
        kennel[1] = new Dog("Arnold",2);
        kennel[2] = new Dog("Fido",3);
        kennel[3] = new Dog("Spot",4);
        kennel[4] = new Dog("Rover",5);
    }
}

For starters, this works, but seems wrong. Why do I have to start with Dog[] … new Dog[5]? Maybe stupid question… I’m new to this.

Anyway… What I have been asked to do is use the “enhanced” for loop to iterate through the array calling bark().

So with a traditional for loop it would look like this:

for (i=0;i<kennel.length;i++)
{
    kennel[i].bark();
}

Simple stuff, right? But how do I implement this using the for(type item : array) syntax?

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  1. Editorial Team
    Editorial Team
    2026-05-30T18:41:29+00:00Added an answer on May 30, 2026 at 6:41 pm

    Just use it in the for each

    for(Dog d : kennel) {
        d.bark();
    }
    
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