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Asked: 2026-06-18T05:46:30+00:00

Ok, so I have been reading every google result about creating an array of

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Ok, so I have been reading every google result about creating an array of linkedlist, and most of the stack overflow threads, but I don’t really understand what they are doing. Do I need to create a seperate class that extends linkedlist and then create an array of that class?

I have tried a million different ways of arranging this code, but this is what I have at the moment.

public static int[][] genPerms(int numElements, int totPerms) {
    int permArray[][] = new int[totPerms][numElements];
    LinkedList<Integer>[] elementsLeftList = new LinkedList<Integer>[numElements];

The error is generic array creation. Can someone explain to me what is actually going on here.

In addition to the solutions below I was told you can create an array of head pointers.

Thanks in advance.

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1 Answer

  1. Editorial Team

    You can’t currently create an array of generics in Java without going through a complicated process. Can you do the following instead?

    List<LinkedList<Integer>> elementsLeftList = new ArrayList<LinkedList<Integer>>();

    If you really need it as an array you can then get it from elementsLeftList.toArray() and cast the result.

    You can read the following link for the explanation: http://www.angelikalanger.com/GenericsFAQ/FAQSections/ParameterizedTypes.html#FAQ104

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