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Home/ Questions/Q 7027441
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T00:14:51+00:00 2026-05-28T00:14:51+00:00

ok so i have this code so far: for (int i = 0; i

  • 0

ok so i have this code so far:

           for (int i = 0; i < fajlovi.Length ; i++)
        {
            string filename = fajlovi[i];
            string link = Server.MapPath("~/upload" + "//" + Page.User.Identity.Name) + fajlovi[i];
            LinkButton button = new LinkButton();
            button.Text = "Download";
            button.PostBackUrl = link;
            GridViewRow row = new GridViewRow(i, i, DataControlRowType.DataRow, DataControlRowState.Normal);



        }

now what i need is to add the string filename and the linkbutton button to a row in a GridView. i know that i need to create a GridViewRow and then add that row to the GridView, but i have no idea how to add the elements into the row.

Anyone know how to work with this?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-28T00:14:52+00:00Added an answer on May 28, 2026 at 12:14 am

    The elements must be added to a TableCell, which in turn must be added to the GridViewRow:

            // Filename
            string filename = "...";
            Label lbl_filename = new Label();
            lbl_filename.Text = filename;
            // ...
    
            // Button
            LinkButton button = new LinkButton();
            button.Text = "Download";
            // ...
    
            GridViewRow row = new GridViewRow(i, i, DataControlRowType.DataRow, DataControlRowState.Normal);
            TableCell cell = new TableCell();
            cell.ColumnSpan = some_columnspan;
            cell.HorizontalAlign = HorizontalAlign.Left;
            cell.Controls.Add(lbl_filename); // add control
            cell.Controls.Add(button); // add control
            row.Cells.Add(cell);
    
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