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Home/ Questions/Q 1088595
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T23:05:28+00:00 2026-05-16T23:05:28+00:00

Ok so I have three tables like so Students Name StudendId ———————- John 1

  • 0

Ok so I have three tables like so

Students

Name        StudendId
----------------------
John            1
Jane            2
Bob             3
Betty           4

Class

StudentId   TeacherId
----------------------
1            1
2            2
3            1
4            2
1            3
4            3

Teacher

Name          TeacherId
------------------------
Jim               1
Joan              2
Jill              3

Ok so I want to find the teacher who is teaching both john and bob.

So far my query is,

 select distinct Teachers.Name from Teachers, 
   ((select Teachers.Name from Class, Students 
     where Students.StudendId = Class.StudentId and Students.Name = 'John') as tbl1
    join
   (select Class.TeacherId from Class, Students 
     where Students.StudendId = Class.StudentId and Students.Name = 'Bob') as tbl2
   on tbl1.TeacherId = tbl2.TeacherId) where Teachers.TeacherId = tbl1.TeacherId;

So I wondering if this is the optimal way of constructing a query? I worry about this approach is that it doesn’t seem to scale well as could be asking the common teacher of 25 students.

Thanks,
Vinh

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T23:05:28+00:00Added an answer on May 16, 2026 at 11:05 pm

    Use:

      SELECT t.name
        FROM TEACHERS t
        JOIN CLASS c ON c.teacherid = t.teacherid
        JOIN STUDENTS s ON s.studentid = c.studentid
                       AND s.name IN ('John', 'Bob')
    GROUP BY t.name
      HAVING COUNT(DISTINCT s.name) = 2
    

    The HAVING COUNT(DISTINCT s.name) must equal the number of names specified in the IN clause, because IN means the names could be John or Bob, in addition to teachers to have both students. The DISTINCT insulates from the possibility of duplicate names (2x John, etc), which would be a false positive.

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