Question

Ok so I just read this question Do you ever use the volatile keyword in Java?, and I get using a volatile variable in order to stop a loop. Also I’ve seen this reference, http://www.javamex.com/tutorials/synchronization_volatile.shtml. Now the article says that volatile variables are non-blocking. Also it says that it cannot be used for concurrency in a read-update-write sequence. Which makes sense because they’re non-blocking.

Since volatile variables are never cached is it faster to simply use synchronization to stop the loop (from the earlier link)?

Edit: Using a synchronized solution

public class A{
  private boolean test;

  public A(){
    test = true;
  }

  public synchronized void stop(){
    test = false;
  }

  public synchronized boolean isTrue(){
    return test;
  }
}

public class B extends Thread {
  private A a;

  public B(A refA){
    a = refA;
  }

  public void run(){
    //Does stuff here
    try{
      sleep(1000);
    }
    catch(Exception e){}
    a.stop();
  }

  public static void main(String [] args){
    A TestA = new A();
    B TestB = new B(TestA);
    TestB.start();
    while(TestA.isTrue()){
      //stay in loop
      System.out.println("still in loop");
    }
    System.out.println("Done with loop");
  }
 }

Answer 1

No, reading a volatile variable is faster than than reading an non-volatile variable in a synchronized block.

A synchronized block clears the cached values on entry which is the same as reading a volatile variable. But, it also flushes any cached writes to main memory when the synchronized block is exited, which isn’t necessary when reading volatile variable.