Question

Ok so I know to generate a random number one would create a method such as this:

private int RandomNumber(int min, int max)
{
Random random = new Random();
return random.Next(min, max);
}

Now lets say instead of having it take two numbers example:

RandomNumber(4, 25);

I want it to make the max a value that will be determined, example:

RandomNumber(0, Alist.Count);

Is there any way to do this? I tried making AList.Count = another int number and putting that in but to no avail.

Answer 1

Yes, RandomNumber(0, Alist.Count) will work perfectly. However, instead of making a function for that, you should be using one instance of Random:

Random r = new Random();
DoSomething(r.Next(0, Alist.Count));
DoSomething(r.Next(0, Alist.Count));
DoSomething(r.Next(0, Alist.Count));
// etc., whatever you want.

Edit: So you want a random element from a list?

Random r = new Random();
Alist[r.Next(0, Alist.Count)] // There's your random element.