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Home/ Questions/Q 7169375
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T14:58:35+00:00 2026-05-28T14:58:35+00:00

Ok so I’ve been looking into interpolation lately. Sadly almost every article I’ve read

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Ok so I’ve been looking into interpolation lately. Sadly almost every article I’ve read only discusses interpolation at a decimal level 0.0 to 1.0 to be exact. I would like to interpolate whole number integers regardless of how big they are or if there negative or whatever. I’ve accomplished this with linear interpolation:

public int interpolate(int y1, int y2, int length, int x){
    return y1 + x * (y2 - y1) / (length-1);
}

However I’m stuck with cosine interpolation. This great article talks about cosine interpolation however it’s on a system of numbers from 0.0 to 1.0 as stated above. Here is what I have so far:

public int interpolate(int y1, int y2, int length, int x){
    int v = (int)(y2 - Mathf.Cos(x * 3.1415f))/2;
    return (y1 + x * (y2 - y1) / (length-1)) * v;
}

It doesn’t work though it returns an almost random number with no real direction making it not smooth at all. This is where I need your help. Long story short: How do I make a cosine interpolation function that deals with integers?

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  1. Editorial Team
    Editorial Team
    2026-05-28T14:58:36+00:00Added an answer on May 28, 2026 at 2:58 pm

    Output of cos θ varies from 1 to -1 to 1 as its input ranges from [0, 2π]. We need something from [0, 1]. So

    1. Limit the domain to [0, π] to limit codomain to [1, -1]
    2. Subtract from 1, for codomain to be [0, 2]
    3. Divide by 2 to get a codomain of [0, 1]

    You’ve get a nice function that goes from 0 to 1. The rest is transforming the argument.

    Essentially you need

    (int) ((1 - cos(pi*x / (length-1)))/2 * (y2-y1)+y2)
    
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