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Home/ Questions/Q 1927962
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T06:55:21+00:00 2026-05-17T06:55:21+00:00

Ok SQL and Oracle gurus I have a somewhat complicated query that I’m trying

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Ok SQL and Oracle gurus I have a somewhat complicated query that I’m trying to build.

Here is my current query:

select distinct person_info.person_name
     table2.value,
     table3.value,
     table4.value,
     table5.value
from person_info
    left join table2 on table2.person_name=person_info.person_name
    left join table3 on table3.person_name=person_info.person_name
    left join table4 on table4.person_name=person_info.person_name
    left join table5 on table5.person_name=person_info.person_name;

The primary key for every table is both the person_name and a timestamp. Now my problem is that if multiple instances of the same person_name exist in a table then I only want to left join on the most recent one. Does anyone know how to add this behavior to this query? I am using Oracle.

Thanks!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-17T06:55:21+00:00Added an answer on May 17, 2026 at 6:55 am

    Try:

    select distinct person_info.person_name
         t2.value,
         t3.value,
         t4.value,
         t5.value
    from person_info
        left join (select t.*, row_number() over (partition by person_name order by timestamp_column desc) rowno from table2 t) t2 
             on t2.person_name=person_info.person_name and t2.rowno=1
        left join (select t.*, row_number() over (partition by person_name order by timestamp_column desc) rowno from table3 t) t3
             on t3.person_name=person_info.person_name and t3.rowno=1
        left join (select t.*, row_number() over (partition by person_name order by timestamp_column desc) rowno from table4 t) t4
             on t4.person_name=person_info.person_name and t4.rowno=1
        left join (select t.*, row_number() over (partition by person_name order by timestamp_column desc) rowno from table5 t) t5
             on t5.person_name=person_info.person_name and t5.rowno=1;
    
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